154=h^2+3h

Solution for 154=h^2+3h equation:

154=h^2+3h

We move all terms to the left:

154-(h^2+3h)=0

We get rid of parentheses

-h^2-3h+154=0

We add all the numbers together, and all the variables

-1h^2-3h+154=0

a = -1; b = -3; c = +154;
Δ = b2-4ac
Δ = -32-4·(-1)·154
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-25}{2*-1}=\frac{-22}{-2}
=+11
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+25}{2*-1}=\frac{28}{-2}
=-14
$